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Instrumentation

4-20 mA shunt resistor selection: 250 ohm and 500 ohm examples

Convert a 4-20 mA loop into a voltage signal with Ohm's Law while checking resistor power, input impedance, loop burden, tolerance, and existing receiver hardware.

Product
4-20 mA current loops
Level
Field triage
Read time
9 min
Reviewed
2026-07-18
Public technical overview

What to establish before troubleshooting

A resistor placed across a voltage input converts loop current to voltage through V = I x R. A 250 ohm resistor produces 1 V at 4 mA and 5 V at 20 mA; a 500 ohm resistor produces 2-10 V.

The resistor is also part of the loop burden. At 20 mA, 250 ohms consumes 5 V of loop compliance and dissipates 0.10 W, while 500 ohms consumes 10 V and dissipates 0.20 W. The loop supply must still cover the transmitter, wiring, barriers, isolators, and every receiver.

Abbreviated worked example

Check a 250 ohm 1-5 V conversion

A 4-20 mA transmitter is connected to a voltage input through a documented 250 ohm precision shunt resistor.

  1. 1At 4 mA: 0.004 A x 250 ohms = 1.00 V.
  2. 2At 20 mA: 0.020 A x 250 ohms = 5.00 V; resistor power is I squared x R = 0.10 W.

Result: The nominal converted signal is 1-5 V, provided the loop has at least 5 V of spare compliance for the resistor.

Caution: Select resistance, tolerance, temperature coefficient, and power rating from the installed device requirements. Do not assume a nominal quarter-watt part provides the needed design margin or measurement accuracy.

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Product
4-20 mA current loops
Level
Field triage
Sources
2
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4-20 mA shunt resistor selection: 250 ohm and 500 ohm examples | Automation Controls Toolbox